[Webkit-unassigned] [Bug 244018] 'a\n' is considered as a variable

[bugzilla-daemon at webkit.org]

https://bugs.webkit.org/show_bug.cgi?id=244018

--- Comment #3 from Karl Dubost <karlcow at apple.com> ---
Full Safari output

```
TypeError: a
 is not a function. (In 'a
()', 'a
' is 1)
```

I wonder if it would be better to actually shows the output as:

```
TypeError: a\n is not a function. (In 'a\n()', 'a\n' is 1)
```

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