[Webkit-unassigned] [Bug 130723] New: Web Inspector: AXI: expose "busy" status of current and ancestor nodes

bugzilla-daemon at webkit.org bugzilla-daemon at webkit.org
Tue Mar 25 10:08:24 PDT 2014


https://bugs.webkit.org/show_bug.cgi?id=130723

           Summary: Web Inspector: AXI: expose "busy" status of current
                    and ancestor nodes
           Product: WebKit
           Version: 528+ (Nightly build)
          Platform: All
        OS/Version: All
            Status: NEW
          Severity: Normal
          Priority: P2
         Component: Web Inspector
        AssignedTo: webkit-unassigned at lists.webkit.org
        ReportedBy: jcraig at apple.com
                CC: timothy at apple.com, joepeck at webkit.org,
                    webkit-bug-importer at group.apple.com,
                    graouts at webkit.org


Web Inspector: AXI: expose "busy" status of current and ancestor nodes

If an element is inside an ancestor marked as busy, we should expose this. 

It will also be useful for validation. For example, elements without required owned children (empty lists or menus, empty grids) are only valid when they are hidden or busy.

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