[Webkit-unassigned] [Bug 130723] New: Web Inspector: AXI: expose "busy" status of current and ancestor nodes
bugzilla-daemon at webkit.org
bugzilla-daemon at webkit.org
Tue Mar 25 10:08:24 PDT 2014
https://bugs.webkit.org/show_bug.cgi?id=130723
Summary: Web Inspector: AXI: expose "busy" status of current
and ancestor nodes
Product: WebKit
Version: 528+ (Nightly build)
Platform: All
OS/Version: All
Status: NEW
Severity: Normal
Priority: P2
Component: Web Inspector
AssignedTo: webkit-unassigned at lists.webkit.org
ReportedBy: jcraig at apple.com
CC: timothy at apple.com, joepeck at webkit.org,
webkit-bug-importer at group.apple.com,
graouts at webkit.org
Web Inspector: AXI: expose "busy" status of current and ancestor nodes
If an element is inside an ancestor marked as busy, we should expose this.
It will also be useful for validation. For example, elements without required owned children (empty lists or menus, empty grids) are only valid when they are hidden or busy.
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