[Webkit-unassigned] [Bug 135311] New: Web Inspector: shown() called on a content view when stepping over an instruction in the debugger

bugzilla-daemon at webkit.org bugzilla-daemon at webkit.org
Fri Jul 25 16:19:43 PDT 2014


https://bugs.webkit.org/show_bug.cgi?id=135311

           Summary: Web Inspector: shown() called on a content view when
                    stepping over an instruction in the debugger
           Product: WebKit
           Version: 528+ (Nightly build)
          Platform: All
        OS/Version: All
            Status: NEW
          Severity: Normal
          Priority: P2
         Component: Web Inspector
        AssignedTo: webkit-unassigned at lists.webkit.org
        ReportedBy: sbarati at apple.com
                CC: timothy at apple.com, joepeck at webkit.org,
                    webkit-bug-importer at group.apple.com,
                    graouts at webkit.org


shown() is called on a ContentView every time the debugger steps over the instruction.

Do we want to keep these semantics? If so, I'd argue it's apt to rename this function because it doesn't necessarily match when the screen is actually 'shown'.
Or maybe, we should prevent screens that are already visible from having 'shown' called on them.

The origin of the shown() is probably caused by an event from DebuggerManager every time it steps over a function.

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