[Webkit-unassigned] [Bug 135311] New: Web Inspector: shown() called on a content view when stepping over an instruction in the debugger
bugzilla-daemon at webkit.org
bugzilla-daemon at webkit.org
Fri Jul 25 16:19:43 PDT 2014
https://bugs.webkit.org/show_bug.cgi?id=135311
Summary: Web Inspector: shown() called on a content view when
stepping over an instruction in the debugger
Product: WebKit
Version: 528+ (Nightly build)
Platform: All
OS/Version: All
Status: NEW
Severity: Normal
Priority: P2
Component: Web Inspector
AssignedTo: webkit-unassigned at lists.webkit.org
ReportedBy: sbarati at apple.com
CC: timothy at apple.com, joepeck at webkit.org,
webkit-bug-importer at group.apple.com,
graouts at webkit.org
shown() is called on a ContentView every time the debugger steps over the instruction.
Do we want to keep these semantics? If so, I'd argue it's apt to rename this function because it doesn't necessarily match when the screen is actually 'shown'.
Or maybe, we should prevent screens that are already visible from having 'shown' called on them.
The origin of the shown() is probably caused by an event from DebuggerManager every time it steps over a function.
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