[Webkit-unassigned] [Bug 82775] New: SVG <use> of <symbol> containing <linearGradient> renders black

[bugzilla-daemon at webkit.org]

https://bugs.webkit.org/show_bug.cgi?id=82775

           Summary: SVG <use> of <symbol> containing <linearGradient>
                    renders black
           Product: WebKit
           Version: 528+ (Nightly build)
          Platform: Unspecified
        OS/Version: Unspecified
            Status: NEW
          Severity: Normal
          Priority: P2
         Component: SVG
        AssignedTo: webkit-unassigned at lists.webkit.org
        ReportedBy: schenney at chromium.org
                CC: zimmermann at kde.org


Created an attachment (id=134870)
 --> (https://bugs.webkit.org/attachment.cgi?id=134870&action=review)
Repro case

A <use> element that references a <symbol> element that contains a linearGradient applied to a rect renders the rect as black. If you move the linearGradient out of the symbol and into a <def> block, it renders correctly. It also renders correctly if you do not use the <symbol> and <use> the rect directly.

Failing in Safari trunk and Chromium. Works in an earlier version of Chrome (according to reporter) and in Safari 5.1.2.

I strongly suspect this is due to changes in the <use> element handling, although it may also be due to the changes we made to resource invalidation, or it may be something else entirely.

Chromium http://code.google.com/p/chromium/issues/detail?id=120994

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