[Webkit-unassigned] [Bug 25823] [Qt] Add API to generate a QUrl from a user string url
bugzilla-daemon at webkit.org
bugzilla-daemon at webkit.org
Fri May 22 21:49:44 PDT 2009
https://bugs.webkit.org/show_bug.cgi?id=25823
zecke at selfish.org changed:
What |Removed |Added
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Attachment #30387|review? |review+
Flag| |
------- Comment #4 from zecke at selfish.org 2009-05-22 21:49 PDT -------
(From update of attachment 30387)
> + If that is not the case, an attempt is made to turn the string into a
> + http:// or ftp:// URL. The latter in the case the string starts with
> + 'ftp'. The result is then passed through QUrl's tolerant parser, and
> + in the case or success, a valid QUrl is returned, orelse a QUrl().
orelse??? space missing?
> + QUrl url = view->guessUrlFromString(string);
my taste would say to use the static type QWebView::guessUrlFromString...
ignore that at your will..
are you sure that QWebView is the best place for that? If I have a QWebPage in
a graphics view item I still want to use the guessing and using QWebView might
not feel right. Do you think QWebView is the best place to put it? what about
QWebPage?
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