[webkit-qt] QtWebKit stable branch
loic.yhuel at gmail.com
Wed Dec 19 14:32:50 PST 2012
2012/12/19 Simon Hausmann <simon.hausmann at digia.com>:
> On Wednesday, December 19, 2012 11:16:17 AM Sergio Villar Senin wrote:
>> I'm pretty sure that you have talked about this many times, but if you
>> don't mind to repeat it again, is there any plan to have a stable branch
>> of QtWebKit for the Qt5 release?
> I don't mind repeating it :)
> As QtWebKit is part of the Qt release of the Qt project, we're also
> integrating with its branching model:
> The repository for the release is sitting next to the other module
> repositories of Qt 5 in Qt Gerrit:
> Like all other modules it has three branches:
> release -> Code in here is targetting the next immediate release, deep
> stable -> feature frozen. Changes here should be the result of back-
> porting a fix from WebKit trunk. (see also
> dev -> Theoretically that should be a live-mapping to WebKit trunk, but
> it's not for the simple reason that WebKit trunk as git repo is just too big
> to ask people to clone - it would totally bloat the repo. So instead dev is
> the result of taking snapshots from WebKit trunk.
> So once 5.0.x development has calmed down and 5.1 is kicking in, I (or
> somebody else) will import WebKit trunk snapshots into dev periodically. A Qt
> 5.1 alpha release should be made from that branch according to the project
> model. At some point Qt branches for beta and merges dev into stable and
> produces a beta release. In the case of QtWebKit that merge will be a "git
> merge -s theirs" style, i.e. discarding all changes from stable and taking all
> from dev because everything in stable should be the result of an earlier trunk
> revision plus backports.
> Questions? :)
Looking at the gitorious mirror (http://qt.gitorious.org/qt/qtwebkit),
I see the LayoutTests directory is not in the snapshots.
How can the release branch be tested ? Using the version from the
trunk at the branch point could be wrong, as LayoutTests changes in
cherry-picked commits would be missing.
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